Retrieve data from column as a row.
Lets use employee table from Scott as a an example :
select * from scott.employee;
EMPLOYEE_ID FIRST_NAME LAST_NAME DEPT_NO SALARY
----------- -------------------- -------------------- ---------- ----------
1 Dan Morgan 10 100000
2 Helen Lofstrom 20 100000
3 Akiko Toyota 20 50000
4 Jackie Stough 20 40000
5 Richard Foote 20 70000
6 Joe Johnson 20 30000
7 Clark Urling 20 90000
9 Richard Foote 20 70001
8 Clark Urling 20 90001
Now I want to get the list of all users in a particular department. I want the output to be printed something like this :
I can achieve this by using the simple LISTAGG function provided by Oracle to get this results.In this below example I got ll the users ID,FNAME,LNAME in every dept.
DEPT_NO EMP_DETAILS
10 1:Dan-Morgan
20 2:Helen-Lofstrom,3:Akiko-Toyota,4:Jackie-Stough,5:Richard-Foote,6:Joe- Johnson,7:Clark-Urling,8:Clark-Urling,9:Richard-Foote
Code :
select DEPT_NO,LISTAGG(EMPLOYEE_ID ||':' ||FIRST_NAME||'-'||last_name,',') WITHIN GROUP (order by EMPLOYEE_ID,first_name) "EMP DETAILS" from scott.employee group by dept_no;
usage - we can call listagg function and need to pass the columns that you want to retrieve data from and transform them into rows.
Listagg (column1||'-'||column2) make sure you pass a common column like the deptno thru which you want to group the data.
Lets use employee table from Scott as a an example :
select * from scott.employee;
EMPLOYEE_ID FIRST_NAME LAST_NAME DEPT_NO SALARY
----------- -------------------- -------------------- ---------- ----------
1 Dan Morgan 10 100000
2 Helen Lofstrom 20 100000
3 Akiko Toyota 20 50000
4 Jackie Stough 20 40000
5 Richard Foote 20 70000
6 Joe Johnson 20 30000
7 Clark Urling 20 90000
9 Richard Foote 20 70001
8 Clark Urling 20 90001
Now I want to get the list of all users in a particular department. I want the output to be printed something like this :
I can achieve this by using the simple LISTAGG function provided by Oracle to get this results.In this below example I got ll the users ID,FNAME,LNAME in every dept.
DEPT_NO EMP_DETAILS
10 1:Dan-Morgan
20 2:Helen-Lofstrom,3:Akiko-Toyota,4:Jackie-Stough,5:Richard-Foote,6:Joe- Johnson,7:Clark-Urling,8:Clark-Urling,9:Richard-Foote
Code :
select DEPT_NO,LISTAGG(EMPLOYEE_ID ||':' ||FIRST_NAME||'-'||last_name,',') WITHIN GROUP (order by EMPLOYEE_ID,first_name) "EMP DETAILS" from scott.employee group by dept_no;
usage - we can call listagg function and need to pass the columns that you want to retrieve data from and transform them into rows.
Listagg (column1||'-'||column2) make sure you pass a common column like the deptno thru which you want to group the data.
No comments :
Post a Comment